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(A) The capacitance $C$ of a spherical capacitor with radii $a$ and $b$ $(b > a)$ and dielectric constant $K$ is given by the formula: $C = 4\pi \vare

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$240 \; pF$

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(A) The capacitance $C$ of a spherical capacitor with radii $a$ and $b$ $(b > a)$ and dielectric constant $K$ is given by the formula: $C = 4\pi \varepsilon_0 K \left( \frac{ab}{b - a} ight)$.Given: $a = 9 \; cm = 9 	imes 10^{-2} \; m$,$b = 12 \; cm = 12 	imes 10^{-2} \; m$,$K = 6$,and $\frac{1}{4\pi \varepsilon_0} = 9 	imes 10^9 \; N \cdot m^2/C^2$.Substituting the values:$C = \frac{6}{9 	imes 10^9} 	imes \left( \frac{12 	imes 10^{-2} 	imes 9 	imes 10^{-2}}{12 	imes 10^{-2} - 9 	imes 10^{-2}} ight)$$C = \frac{6}{9 	imes 10^9} 	imes \left( \frac{108 	imes 10^{-4}}{3 	imes 10^{-2}} ight)$$C = \frac{6}{9 	imes 10^9} 	imes (36 	imes 10^{-2})$$C = \frac{216 	imes 10^{-2}}{9 	imes 10^9} = 24 	imes 10^{-11} \; F$$C = 240 	imes 10^{-12} \; F = 240 \; pF$.

The respective radii of the two spheres of a spherical condenser are $12 \; cm$ and $9 \; cm$. The dielectric constant of the medium between them is $6$. The capacity of the condenser will be

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