The product left(1+tan 1^{circ}right)left(1+t | vedclass

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Question

(c)

We have,

$\begin{array}{l}\left(1+	an 1^{\circ}ight)\left(1+	an 2^{\circ}ight)\left(1+	an 3^{\circ}ight) \ 	ext { We know that, }

Vedclass · Accepted Answer

$2^{23}$

Vedclass · Answer

(c)

We have,

$\begin{array}{l}\left(1+	an 1^{\circ}ight)\left(1+	an 2^{\circ}ight)\left(1+	an 3^{\circ}ight) \ 	ext { We know that, } \ (1+	an 	heta)\left(1+	an \left(45^{\circ}-	hetaight)ight)=2 \ 	herefore\left(1+	an 45^{\circ}ight) \ \left(1+	an 43^{\circ}ight)\left(1+	an 44^{\circ}ight)\left(1+	an 2^{\circ}ight) \ \left(1+	an 45^{\circ}ight) \ \Rightarrow \quad 2^{22} \cdot 2=2^{23} \end{array}$

The product $\left(1+\tan 1^{\circ}\right)\left(1+\tan 2^{\circ}\right)\left(1+\tan 3^{\circ}\right)$ $. .\left(1+\tan 45^{\circ}\right)$ equals

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