The probability that a leap year will have $53$ Fridays or $53$ Saturdays is

Statement $- I :$ If the probabilities of solving a problem by $A$ and $B$ are $1/3$ and $1/4$ respectively,then the probability that the problem is solved is $7/12$.
Statement $- II :$ The events described above are independent events.

If $A$ and $B$ are mutually exclusive events,then the value of $P(A \cup B)$ is

$A$ die is thrown. Let $A$ be the event that the number obtained is greater than $3$. Let $B$ be the event that the number obtained is less than $5$. Then $P(A \cup B)$ is

Fill in the blanks in the following table:

$P(A)$	$P(B)$	$P(A \cap B)$	$P(A \cup B)$
$0.5$	$0.35$	$.........$	$0.7$

If $A$ and $B$ are two events such that $P(A) = 0.4$,$P(A \cup B) = 0.7$ and $P(A \cap B) = 0.2$,then $P(B) = $