The probability that a leap year will have 53 | vedclass

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Question

(b) There are $366$ days in a leap year, in which $52$ weeks and two days, The combination of $2$ days -

Sunday -Monday, Monday -Tuesday, Tuesday -

Vedclass · Accepted Answer

$\frac{3}{7}$

Vedclass · Answer

(b) There are $366$ days in a leap year, in which $52$ weeks and two days, The combination of $2$ days -

Sunday -Monday, Monday -Tuesday, Tuesday -Wednesday, Wednesday -Thursday, Thursday -Friday, Friday -Saturday, Saturday -Sunday

$P(53$ Fridays) = $\frac{2}{7}$; $P(53$ Saturdays) $ = \frac{2}{7}$

$P(53$ Fridays and $53$ Saturdays) $ = \frac{1}{7}$

$	herefore$ $P(53$ Fridays or Saturdays) = $P(53$ Fridays$) +  P(53$ Saturdays) $-P(53$ Fridays and Saturdays)

$ = \frac{2}{7} + \frac{2}{7} - \frac{1}{7}$ $ = \frac{3}{7}$.

The probability that a leap year will have $53$ Fridays or $53$ Saturdays is

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