$A$ die is thrown. Let $A$ be the event that the number obtained is greater than $3$. Let $B$ be the event that the number obtained is less than $5$. Then $P(A \cup B)$ is

  • A
    $\frac{3}{5}$
  • B
    $0$
  • C
    $1$
  • D
    $\frac{2}{5}$

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Similar Questions

Fill in the blanks in the following table:
$P(A)$ $P(B)$ $P(A \cap B)$ $P(A \cup B)$
$\frac{1}{3}$ $\frac{1}{5}$ $\frac{1}{15}$ $........$

Suppose that $A, B, C$ are events such that $P(A) = P(B) = P(C) = \frac{1}{4}$,$P(AB) = P(CB) = 0$,and $P(AC) = \frac{1}{8}$. Then find $P(A \cup B)$.

There are three events $A, B, C$,one of which must and only one can happen. The odds are $8:3$ against $A$,$5:2$ against $B$,and the odds against $C$ are $43:17k$. Then the value of $k$ is:

$A$ doctor schedules an appointment for a patient in the month of November. What is the probability that the date is a multiple of $5$ or $6$?

From the employees of a company,$5$ persons are selected to represent them in the managing committee of the company. Particulars of five persons are as follows :
$S.No.$ Name Sex Age in years
$1.$ Harish $M$ $30$
$2.$ Rohan $M$ $33$
$3.$ Sheetal $F$ $46$
$4.$ Alis $F$ $28$
$5.$ Salim $M$ $41$

$A$ person is selected at random from this group to act as a spokesperson. What is the probability that the spokesperson will be either male or over $35$ years?

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