The position of a particle moving along the $y-$ axis is given as $y = 3t^2 - t^3$,where $y$ is in $m$ and $t$ is in $s$. The time when the particle attains the maximum positive position will be ........ $s$.

The position-time $(x-t)$ graph for positive acceleration is

$A$ particle of mass $m$ is constrained to move on the $x$-axis. $A$ force $F$ acts on the particle. $F$ always points toward the position labeled $E$. For example,when the particle is to the left of $E$,$F$ points to the right. The magnitude of $F$ is constant except at point $E$ where it is zero. The system is horizontal. $F$ is the net force acting on the particle. The particle is displaced a distance $A$ towards the left from the equilibrium position $E$ and released from rest at $t=0$. The velocity-time graph of the particle is:

The position $x$ of a particle varies with time $t$ as $x = ct^2 + b$,where $c$ and $b$ are positive constants. Which of the following graphs is correct?

The velocity-time graph of a body is shown in the figure. It implies that at point $B$

The slope of the velocity-time graph for motion with uniform velocity is equal to: