A particle of mass m is constrained to move o | vedclass

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(C) The particle is released from rest at $x = -A$ (left of $E$). Since the force $F$ is constant and directed towards $E$,the acceleration $a = F/m$

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(C) The particle is released from rest at $x = -A$ (left of $E$). Since the force $F$ is constant and directed towards $E$,the acceleration $a = F/m$ is constant and positive (directed to the right). As the particle moves from $x = -A$ to $x = E$,its velocity increases linearly with time: $v(t) = at = (F/m)t$. At $x = E$,the force becomes zero,and the particle passes through $E$ with maximum velocity. Once the particle is to the right of $E$,the force $F$ reverses direction (points to the left),causing a constant negative acceleration $a = -F/m$. The velocity decreases linearly from its maximum value to zero at $x = +A$. This cycle repeats,resulting in a triangular velocity-time graph. Graph $C$ represents this motion correctly.

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