The order of a reaction is said to be $ 2 $ with respect to a reactant $X, $ when
The order of a reaction is said to be $ 2 $ with respect to a reactant $X, $ when
- A
The rate of the reaction is proportional to $[X]$
- B
The rate of the reaction is proportional ${[X]^2}$
- C
Two molecules of $ X$ are present in the stoichiometric equation
- D
The reaction occurs in two steps
Similar Questions
What is the order of reaction $A + B \to C$
Observation
$[A]$
$[B]$
Rate of reaction
$1$
$0.1$
$0.1$
$2 \times {10^{ - 3}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$
$2$
$0.4$
$0.1$
$0.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$
$3$
$0.1$
$0.2$
$1.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$
What is the order of reaction $A + B \to C$
| Observation | $[A]$ | $[B]$ | Rate of reaction |
| $1$ | $0.1$ | $0.1$ | $2 \times {10^{ - 3}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$ |
| $2$ | $0.4$ | $0.1$ | $0.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$ |
| $3$ | $0.1$ | $0.2$ | $1.4 \times {10^{ - 2}}\,mol\,{L^{ - 1}}{\sec ^{ - 1}}$ |
Which of the following is correct ?
Which of the following is correct ?
For a given reaction ${t_{1/2}} = \frac{1}{{Ka}}.$. The order of the reaction is
For a given reaction ${t_{1/2}} = \frac{1}{{Ka}}.$. The order of the reaction is
In the given reaction, ; $K_3 > K_2 > K_1$
then rate determining step will be
In the given reaction, ; $K_3 > K_2 > K_1$
then rate determining step will be
The specific rate constant of a first order reaction depends on the
The specific rate constant of a first order reaction depends on the
- [IIT 1983]