The order of a reaction is said to be $2$ with respect to a reactant $X$,when

  • A
    The rate of the reaction is proportional to $[X]$
  • B
    The rate of the reaction is proportional to $[X]^2$
  • C
    Two molecules of $X$ are present in the stoichiometric equation
  • D
    The reaction occurs in two steps

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Similar Questions

Determine the order of reaction on the basis of following data for the reaction $A + B \to C$.
Exp.$[A]$$[B]$Rate of reaction $(mol \ L^{-1} \ s^{-1})$
$1$$0.1$$0.1$$2 \times 10^{-3}$
$2$$0.4$$0.1$$0.8 \times 10^{-2}$
$3$$0.1$$0.2$$1.6 \times 10^{-2}$
(in $.5$)

The reaction $2 A + B + C \longrightarrow D + E$ is found to be first order in $A$,second order in $B$,and zero order in $C$. What is the effect of increasing the concentration of all reactants twice?

Consider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
Experiment No. $[A] \ (mol \ dm^{-3})$ $[B] \ (mol \ dm^{-3})$ $[C] \ (mol \ dm^{-3})$ Rate of reaction $(mol \ dm^{-3} \ s^{-1})$
$1$ $0.2$ $0.1$ $0.1$ $6.0 \times 10^{-5}$
$2$ $0.2$ $0.2$ $0.1$ $6.0 \times 10^{-5}$
$3$ $0.2$ $0.1$ $0.2$ $1.2 \times 10^{-4}$
$4$ $0.3$ $0.1$ $0.1$ $9.0 \times 10^{-5}$

The rate of the reaction for $[A]=0.15 \ mol \ dm^{-3}, [B]=0.25 \ mol \ dm^{-3}$ and $[C]=0.15 \ mol \ dm^{-3}$ is found to be $Y \times 10^{-5} \ mol \ dm^{-3} \ s^{-1}$. The value of $Y$ is . . . . . .

For the decomposition reaction $2NH_3(g) \rightarrow N_2(g) + 3H_2(g)$,if the rate constant $k = 2.6 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$,calculate the rate of formation of $N_2$ and $H_2$.

The given data are for the reaction:
$2NO_{(g)} + Cl_{2(g)} \to 2NOCl_{(g)}$ at $298 \ K$
Experiment$[Cl_2] \ (M)$$[NO] \ (M)$Rate $(mol \ L^{-1} \sec^{-1})$
$I$$0.05$$0.05$$1 \times 10^{-3}$
$II$$0.15$$0.05$$3 \times 10^{-3}$
$III$$0.05$$0.15$$9 \times 10^{-3}$

The rate law for the reaction is:

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