Statement-I : sim (pleftrightarrow | vedclass

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Question

$ \sim \left( {p \leftrightarrow q} ight) \equiv  \sim \left( {\left( {p 	o q} ight) \wedge \left( {q 	o p} ight)} ight)$

$ \equiv&n

Vedclass · Accepted Answer

Statement$-1$ is True, Statement$-2$ is False.

Vedclass · Answer

$ \sim \left( {p \leftrightarrow q} ight) \equiv  \sim \left( {\left( {p 	o q} ight) \wedge \left( {q 	o p} ight)} ight)$

$ \equiv  \sim \left( {p 	o q} ight) \vee  \sim \left( {q 	o p} ight)$

$ \equiv \left( {p \wedge  - q} ight) \vee  \sim \left( { \sim q \vee p} ight)$

and $p 	o \left( {p + q} ight) \equiv p 	o \left( { \sim p \vee q} ight)$ is not a tautology.

Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.

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