The negation of the Boolean expression ((sim | vedclass

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(C) Let the given expression be $S = ((\sim q) \wedge p) \Rightarrow ((\sim p) \vee q)$.Using the implication rule $A \Rightarrow B \equiv \sim A \vee

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$\sim(p \Rightarrow q)$

Vedclass · Answer

(C) Let the given expression be $S = ((\sim q) \wedge p) \Rightarrow ((\sim p) \vee q)$.Using the implication rule $A \Rightarrow B \equiv \sim A \vee B$,we have:$S \equiv \sim((\sim q) \wedge p) \vee ((\sim p) \vee q)$.Applying De Morgan's law: $\sim((\sim q) \wedge p) \equiv q \vee (\sim p)$.So,$S \equiv (q \vee \sim p) \vee (\sim p \vee q) \equiv \sim p \vee q$.We know that $\sim p \vee q \equiv p \Rightarrow q$.Therefore,the negation of the expression is $\sim(p \Rightarrow q)$.

The negation of the Boolean expression $((\sim q) \wedge p) \Rightarrow ((\sim p) \vee q)$ is logically equivalent to

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The Boolean expression $((p \wedge q) \vee (p \vee \sim q)) \wedge (\sim p \wedge \sim q)$ is equivalent to

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