The motion of a particle of mass m is describ | vedclass

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(A) The position of the particle is given by the equation $y = ut + \frac{1}{2}gt^2$. To find the velocity $v$,we differentiate the position $y$ with

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$mg$

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(A) The position of the particle is given by the equation $y = ut + \frac{1}{2}gt^2$. To find the velocity $v$,we differentiate the position $y$ with respect to time $t$: $v = \frac{dy}{dt} = \frac{d}{dt}(ut + \frac{1}{2}gt^2) = u + gt$. To find the acceleration $a$,we differentiate the velocity $v$ with respect to time $t$: $a = \frac{dv}{dt} = \frac{d}{dt}(u + gt) = g$. According to Newton's second law of motion,the force $F$ acting on the particle is given by $F = ma$. Substituting the value of acceleration,we get $F = m 	imes g = mg$.

The motion of a particle of mass $m$ is described by $y = ut + \frac{1}{2}gt^2$. Find the force acting on the particle.

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