If impulse I varies with time t as Ileft( kg | vedclass

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Question

(b)

The definition of impulse, $I = F d t = m \frac{ dv }{ dt } dt = mdv =$ change in momentum. Thus, $I=20 t^2-40\,t$

For minimum of impulse, $

Vedclass · Accepted Answer

$t=1$

Vedclass · Answer

(b)

The definition of impulse, $I = F d t = m \frac{ dv }{ dt } dt = mdv =$ change in momentum. Thus, $I=20 t^2-40\,t$

For minimum of impulse, $\frac{ dI }{ dt }=0$ or $40\,t -40=0$ or $t =1\,s$

If impulse $I$ varies with time $t$ as $I\left( kg ms ^{-1}\right)=20 f^2-40 t$. The change in momentum is minimum at ........... $s$

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