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(B) The acceleration due to gravity on the surface of a planet is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the universal gravitational c

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$g/5$

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(B) The acceleration due to gravity on the surface of a planet is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the universal gravitational constant,$M$ is the mass of the planet,and $R$ is its radius.For the Earth,$g_e = \frac{GM_e}{R_e^2} = g$.For the Moon,$g_m = \frac{GM_m}{R_m^2}$.Given that $M_m = \frac{M_e}{80}$ and $R_m = \frac{R_e}{4}$.Substituting these values into the formula for $g_m$:$g_m = \frac{G(M_e/80)}{(R_e/4)^2} = \frac{G M_e}{80} 	imes \frac{16}{R_e^2} = \frac{16}{80} 	imes \frac{GM_e}{R_e^2}$.Since $\frac{GM_e}{R_e^2} = g$,we get $g_m = \frac{1}{5} g = g/5$.

The moon's radius is $1/4$ that of the earth and its mass is $1/80$ times that of the earth. If $g$ represents the acceleration due to gravity on the surface of the earth,then the acceleration due to gravity on the surface of the moon is:

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