If a man at the equator would weigh $(3/5)^{th}$ of his weight, the angular speed of the earth is

  • A

    $\sqrt {\frac{2}{5}\,\frac{g}{R}} $

  • B

    $\sqrt {\frac{g}{R}} $

  • C

    $\sqrt {\frac{R}{g}} $

  • D

    $\sqrt {\frac{2}{5}\,\frac{R}{g}} $

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