The median of an ungrouped data and the median calculated when the same data is grouped are always the same. Do you think that this is a correct statement? Give reason.
(N/A) No,this is not a correct statement. The median of ungrouped data and the median calculated from grouped data are not always the same. This is because the formula used for calculating the median of grouped data,$\text{Median} = l + \left( \frac{\frac{n}{2} - cf}{f} \right) \times h$,is based on the assumption that the observations within each class interval are uniformly distributed. In reality,the actual distribution of data within classes may not be uniform,leading to a slight difference between the two values.
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Similar Questions
The median class of the following frequency distribution is ...........
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $6$ $10$ $5$ $6$ $4$ $2$ $2$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $6$ | $10$ | $5$ | $6$ | $4$ | $2$ | $2$ |
Easy
View Solution$Z - M = \ldots \ldots \ldots \times (M - \bar{x})$
Easy
View SolutionThe mode of the following frequency distribution is $37$. Find the missing frequency $x$.
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ Frequency $4$ $7$ $x$ $18$ $15$ $8$ $7$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ |
| Frequency | $4$ | $7$ | $x$ | $18$ | $15$ | $8$ | $7$ |
Medium
View SolutionFind the median of the following frequency distribution:
Class $60-70$ $70-80$ $80-90$ $90-100$ $100-110$ $110-120$ Frequency $5$ $15$ $20$ $30$ $20$ $8$
| Class | $60-70$ | $70-80$ | $80-90$ | $90-100$ | $100-110$ | $110-120$ |
| Frequency | $5$ | $15$ | $20$ | $30$ | $20$ | $8$ |
Medium
View SolutionIn the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$,$u_{i} =$ .........
Easy
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