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(D) To find the median,we first calculate the cumulative frequency $(cf)$:ClassFrequency $(f)$Cumulative Frequency $(cf)$$60-70$$5$$5$$70-80$$15$$20$$

Vedclass · Accepted Answer

$93$

Vedclass · Answer

(D) To find the median,we first calculate the cumulative frequency $(cf)$:ClassFrequency $(f)$Cumulative Frequency $(cf)$$60-70$$5$$5$$70-80$$15$$20$$80-90$$20$$40$$90-100$$30$$70$$100-110$$20$$90$$110-120$$8$$98$Total frequency $N = 98$. So,$N/2 = 98/2 = 49$.The cumulative frequency just greater than $49$ is $70$,which corresponds to the class interval $90-100$. Thus,the median class is $90-100$.Here,$l = 90$,$f = 30$,$cf = 40$,and $h = 10$.Using the formula: $	ext{Median} = l + \left( \frac{\frac{N}{2} - cf}{f} ight) 	imes h$$	ext{Median} = 90 + \left( \frac{49 - 40}{30} ight) 	imes 10$$	ext{Median} = 90 + \left( \frac{9}{30} ight) 	imes 10 = 90 + 3 = 93$.

Class	$0-50$	$50-100$	$100-150$	$150-200$	$200-250$	$250-300$	$300-350$
Frequency	$10$	$15$	$30$	$20$	$15$	$8$	$2$

Class	$0-20$	$20-40$	$40-60$	$60-80$	$80-100$
Frequency	$5$	$15$	$20$	$18$	$2$

Height (in $cm$)	Frequency	Cumulative frequency
$150-155$	$12$	$a$
$155-160$	$b$	$25$
$160-165$	$10$	$c$
$165-170$	$d$	$43$
$170-175$	$e$	$48$
$175-180$	$2$	$f$
Total	$50$	-

Marks	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Number of students	$2$	$4$	$7$	$6$	$1$

Find the median of the following frequency distribution:

Class $60-70$ $70-80$ $80-90$ $90-100$ $100-110$ $110-120$

Frequency $5$ $15$ $20$ $30$ $20$ $8$

Similar Questions

Find the mean,median and mode of the following frequency distribution:

Class $0-50$ $50-100$ $100-150$ $150-200$ $200-250$ $250-300$ $300-350$

Frequency $10$ $15$ $30$ $20$ $15$ $8$ $2$

Find the median of the following frequency distribution:
Class $0-20$ $20-40$ $40-60$ $60-80$ $80-100$
Frequency $5$ $15$ $20$ $18$ $2$

Find the unknown entries $a, b, c, d, e, f$ in the following distribution of heights of students in a class:

Height (in $cm$) Frequency Cumulative frequency

$150-155$ $12$ $a$

$155-160$ $b$ $25$

$160-165$ $10$ $c$

$165-170$ $d$ $43$

$170-175$ $e$ $48$

$175-180$ $2$ $f$

Total $50$ -

If $x_{i}$ are the midpoints of the class intervals of grouped data,$f_{i}$ are the corresponding frequencies,and $\bar{x}$ is the mean,then $\sum (f_{i} x_{i} - f_{i} \bar{x})$ is equal to

Calculate the mean of the scores of $20$ students in a mathematics test:

Marks $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

Number of students $2$ $4$ $7$ $6$ $1$

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Class	$60-70$	$70-80$	$80-90$	$90-100$	$100-110$	$110-120$
Frequency	$5$	$15$	$20$	$30$	$20$	$8$

Find the median of the following frequency distribution: Class $60-70$ $70-80$ $80-90$ $90-100$ $100-110$ $110-120$ Frequency $5$ $15$ $20$ $30$ $20$ $8$