In the formula bar{x} = A + frac{Sigma f_{i} | vedclass

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(C) The given formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} 	imes c$ represents the Step-Deviation Method for calculating the mean o

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$\frac{x_{i} - A}{c}$

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(C) The given formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} 	imes c$ represents the Step-Deviation Method for calculating the mean of grouped data.In this formula,$A$ is the assumed mean,$c$ is the class size (width),and $x_{i}$ is the class mark.The variable $u_{i}$ is defined as the deviation of the class mark from the assumed mean,divided by the class size.Therefore,$u_{i} = \frac{x_{i} - A}{c}$.

Income (in $Rs.$)	Number of families
$0-5000$	$8$
$5000-10000$	$26$
$10000-15000$	$41$
$15000-20000$	$16$
$20000-25000$	$3$
$25000-30000$	$3$
$30000-35000$	$2$
$35000-40000$	$1$

Weekly income	Number of families
$0-1000$	$250$
$1000-2000$	$190$
$2000-3000$	$100$
$3000-4000$	$40$
$4000-5000$	$15$
$5000-6000$	$5$
Total	$600$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$,$u_{i} =$ .........

Similar Questions

In the formula $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$ for the mean,$d_{i} = \dots$

$\sum_{i=1}^{10} (x_i - \bar{x}) = \dots$

Construction of a cumulative frequency table is useful in determining the

The monthly income of $100$ families is given as follows:

Income (in $Rs.$) Number of families

$0-5000$ $8$

$5000-10000$ $26$

$10000-15000$ $41$

$15000-20000$ $16$

$20000-25000$ $3$

$25000-30000$ $3$

$30000-35000$ $2$

$35000-40000$ $1$

Calculate the modal income (in $Rs.$).

Weekly income of $600$ families is tabulated below:

Weekly income Number of families

$0-1000$ $250$

$1000-2000$ $190$

$2000-3000$ $100$

$3000-4000$ $40$

$4000-5000$ $15$

$5000-6000$ $5$

Total $600$

Compute the median income (in $Rs.$).

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