The mean deviation from the median for the following data is
$x_i$$2$$3$$5$$7$$9$
$f_i$$8$$6$$4$$2$$1$

  • A
    $\frac{94}{21}$
  • B
    $\frac{12}{7}$
  • C
    $\frac{10}{7}$
  • D
    $\frac{100}{21}$

Explore More

Similar Questions

If the mean deviation about the median for the numbers $3, 5, 7, 2k, 12, 16, 21, 24$ arranged in ascending order is $6$,then the median is:

Find the mean deviation about the mean for the following data:
Income per dayNumber of persons
$0-100$$4$
$100-200$$8$
$200-300$$9$
$300-400$$10$
$400-500$$7$
$500-600$$5$
$600-700$$4$
$700-800$$3$

Calculate the mean deviation about the median age for the age distribution of $100$ persons given below:
Age (in years) $16-20$ $21-25$ $26-30$ $31-35$ $36-40$ $41-45$ $46-50$ $51-55$
Number of persons $5$ $6$ $12$ $14$ $26$ $12$ $16$ $9$

Difficult
View Solution

The mean deviation about the mean for the following data is
Class Interval$0$–$2$$2$–$4$$4$–$6$$6$–$8$$8$–$10$
Frequency$1$$3$$4$$1$$2$

Find the mean deviation about the median for the data $36, 72, 46, 42, 60, 45, 53, 46, 51, 49$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo