The mean and standard deviation of a group of $100$ observations were found to be $20$ and $3,$ respectively. Later on it was found that three observations were incorrect, which were recorded as $21,21$ and $18 .$ Find the mean and standard deviation if the incorrect observations are omitted.
Number of observations $(n)=100$
Incorrect mean $(\bar{x})=20$
Incorrect standard deviation $(\sigma)=3$
$ \Rightarrow 20 = \frac{1}{{100}}\sum\limits_{i = 1}^{300} {{x_i}} $
$ \Rightarrow \sum\limits_{i = 1}^{100} {{x_i}} = 20 \times 100 = 2000$
Incorrect sum of observations $=2000$
$\Rightarrow$ Correct sum of observations $=2000-21-21-18=2000-60=1940$
If the variance of the following frequency distribution is $50$ then $x$ is equal to:
Class | $10-20$ | $20-30$ | $30-40$ |
Frequency | $2$ | $x$ | $2$ |
The mean and variance of the marks obtained by the students in a test are $10$ and $4$ respectively. Later, the marks of one of the students is increased from $8$ to $12$ . If the new mean of the marks is $10.2.$ then their new variance is equal to :
The variance of the first $n$ natural numbers is
For a given distribution of marks mean is $35.16$ and its standard deviation is $19.76$. The co-efficient of variation is..
If the mean and variance of eight numbers $3,7,9,12,13,20, x$ and $y$ be $10$ and $25$ respectively, then $\mathrm{x} \cdot \mathrm{y}$ is equal to