The mass of the moon is frac{1}{{81}} of the | vedclass

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Question

(b) Gravitational pull depends upon the acceleration due to gravity on that planet.

${M_m} = \frac{1}{{81}}{M_e}$,${g_m} = \frac{1}{6}{g_e}$

$g

Vedclass · Accepted Answer

The radius of the earth is $\frac{9}{{\sqrt 6 }}$ of the moon

Vedclass · Answer

(b) Gravitational pull depends upon the acceleration due to gravity on that planet.

${M_m} = \frac{1}{{81}}{M_e}$,${g_m} = \frac{1}{6}{g_e}$

$g = \frac{{GM}}{{{R^2}}}$==>$\frac{{{R_e}}}{{{R_m}}} = {\left( {\frac{{{M_e}}}{{{M_m}}} 	imes \frac{{{g_m}}}{{{g_e}}}} ight)^{1/2}}$=${\left( {81 	imes \frac{1}{6}} ight)^{1/2}}$

$	herefore$ ${R_e} = \frac{9}{{\sqrt 6 }}{R_m}$

The mass of the moon is $\frac{1}{{81}}$ of the earth but the gravitational pull is $\frac{1}{6}$ of the earth. It is due to the fact that

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