The mass and diameter of a planet are twice t | vedclass

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Question

$g=\frac{G M}{R^{2}}$ and $g^{\prime}=\frac{G \cdot 2 M}{4 R^{2}}$

$=\frac{1}{2} g$

$T \propto \frac{1}{\sqrt{g}} \Rightarrow \frac{T_{2}}{T_{1}

Vedclass · Accepted Answer

$2 \sqrt{2}$ seconds

Vedclass · Answer

$g=\frac{G M}{R^{2}}$ and $g^{\prime}=\frac{G \cdot 2 M}{4 R^{2}}$

$=\frac{1}{2} g$

$T \propto \frac{1}{\sqrt{g}} \Rightarrow \frac{T_{2}}{T_{1}}=\sqrt{\frac{g_{1}}{g_{2}}}$

$T=\sqrt{\frac{g}{g / 2}}=\sqrt{2}$

$	herefore T_{2}=\sqrt{2} T_{1}=2 \sqrt{2} \mathrm{s}$

The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this planet if it is a seconds pendulum on earth ?

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