The mass of a hydrogen molecule is 3.32 times | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\begin{array}{l}
Change\,in\,momentum\
\Delta P = \frac{P}{{\sqrt 2 }}\hat j + \frac{P}{{\sqrt 2 }}\hat j + \frac{P}{{\sqrt 2 }}\hat i - \frac{P}{

Vedclass · Accepted Answer

$2.35 	imes 10^3$ $ N/m^2$

Vedclass · Answer

$\begin{array}{l}
Change\,in\,momentum\
\Delta P = \frac{P}{{\sqrt 2 }}\hat j + \frac{P}{{\sqrt 2 }}\hat j + \frac{P}{{\sqrt 2 }}\hat i - \frac{P}{{\sqrt 2 }}\hat i\
\Delta P = \frac{{2P}}{{\sqrt 2 }}\hat j = {I_H}\,molecule\
 \Rightarrow \,{I_{wall}} =  - \frac{{2P}}{{\sqrt 2 }}\hat j
\end{array}$

$\begin{array}{l}
pressure,P\
 = \frac{F}{A} = \frac{{\sqrt 2 P}}{A}n\,\,\,\,\,\left( {\,n = no.of\,particles} ight)\
 = \frac{{\sqrt 2  	imes 3.32 	imes {{10}^{ - 27}} 	imes {{10}^3} 	imes {{10}^{23}}}}{{2 	imes {{10}^{ - 4}}}}\
 = 2.35 	imes {10^3}N/{m^2}
\end{array}$

The mass of a hydrogen molecule is $3.32 \times 10^{-27 } $ $kg$. If $10^{23}$ hydrogen molecules strike, per second, a fixed wall of area $2$ $cm^2$ at an angle of $45^o $ to the normal, and rebound elastically with a speed of $10^3\ m/s$, then the pressure on the wall is nearly:

Similar Questions

Consider the following statement: When jumping from some height, you should bend your knees as you come to rest, instead of keeping your legs stiff. Which of the following relations can be useful in explaining the statement

When the speed of a moving body is doubled

The magnitude of force acting on a particle moving along $x$-axis varies with time $(t)$ as shown in figure. If at $t=0$ the velocity of particle is $v_0$, then its velocity at $t=T_0$ will be

The momentum is most closely related to