When the speed of a moving body is doubled:

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(B) The momentum $p$ of a body is defined as the product of its mass $m$ and its velocity $v$,given by the formula $p = mv$.Since the mass $m$ of the

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Its momentum is doubled

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(B) The momentum $p$ of a body is defined as the product of its mass $m$ and its velocity $v$,given by the formula $p = mv$.Since the mass $m$ of the body remains constant,the momentum $p$ is directly proportional to the speed $v$ $(p \propto v)$.When the speed is doubled $(v' = 2v)$,the new momentum $p'$ becomes $p' = m(2v) = 2(mv) = 2p$.Therefore,the momentum of the body is doubled.Kinetic energy $K = \frac{1}{2}mv^2$ would increase by a factor of $4$,not $2$.

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