The length of the minute hand of a clock is 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The minute hand of a clock sweeps a circular sector in a given time interval.Given radius $r = 12\,cm$.In $60$ minutes,the minute hand completes o

Vedclass · Accepted Answer

$37.68$

Vedclass · Answer

(B) The minute hand of a clock sweeps a circular sector in a given time interval.Given radius $r = 12\,cm$.In $60$ minutes,the minute hand completes one full rotation $(360^{\circ})$.Therefore,in $5$ minutes,the angle swept $	heta = \frac{360^{\circ}}{60} 	imes 5 = 30^{\circ}$.The area of the sector swept is given by the formula: $	ext{Area} = \frac{	heta}{360^{\circ}} 	imes \pi r^2$.Substituting the values: $	ext{Area} = \frac{30}{360} 	imes 3.14 	imes 12 	imes 12$.$	ext{Area} = \frac{1}{12} 	imes 3.14 	imes 144 = 3.14 	imes 12 = 37.68\,cm^2$.

Part $I$	Part $II$
$1. \overline{OA} \cup \overline{OB} \cup \widehat{APB}$	$a. \text{Major sector}$
$2. \overline{AB} \cup \widehat{AQB}$	$b. \text{Minor segment}$
$3. \overline{AB} \cup \widehat{APB}$	$c. \text{Minor sector}$
$4. \overline{OA} \cup \overline{OB} \cup \widehat{AQB}$	$d. \text{Major segment}$

The length of the minute hand of a clock is $12\,cm$. The area of the region swept by it in $5$ minutes is $\ldots \ldots \ldots \,cm^2$. $(\pi=3.14)$

Similar Questions

The length of the minute hand of a clock is $14\, cm$. The area of the region swept by it in $10$ minutes is $\ldots \ldots \ldots \, cm^2$.

The diameter of a circle with area $38.5 \, m^2$ is $\ldots \ldots \ldots \ldots m$.

The area of a square inscribed in a circle with radius $70 \, cm$ is $\ldots \ldots \ldots \, cm^2$.

Find the area of the sector of a circle of radius $5\, cm$,if the corresponding arc length is $3.5\, cm$. (in $cm^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module