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(B) The minute hand of a clock sweeps a circular sector in a given time interval.Given radius $r = 12\,cm$.In $60$ minutes,the minute hand completes o

Vedclass · Accepted Answer

$37.68$

Vedclass · Answer

(B) The minute hand of a clock sweeps a circular sector in a given time interval.Given radius $r = 12\,cm$.In $60$ minutes,the minute hand completes one full rotation $(360^{\circ})$.Therefore,in $5$ minutes,the angle swept $	heta = \frac{360^{\circ}}{60} 	imes 5 = 30^{\circ}$.The area of the sector swept is given by the formula: $	ext{Area} = \frac{	heta}{360^{\circ}} 	imes \pi r^2$.Substituting the values: $	ext{Area} = \frac{30}{360} 	imes 3.14 	imes 12 	imes 12$.$	ext{Area} = \frac{1}{12} 	imes 3.14 	imes 144 = 3.14 	imes 12 = 37.68\,cm^2$.

The length of the minute hand of a clock is $12\,cm$. The area of the region swept by it in $5$ minutes is $\ldots \ldots \ldots \,cm^2$. $(\pi=3.14)$

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