The perimeter of a semicircular table-top is $3.60\,m .$ Then, its radius is $\ldots \ldots \ldots . . cm .$
The perimeter of a semicircular table-top is $3.60\,m .$ Then, its radius is $\ldots \ldots \ldots . . cm .$
- A
$35$
- B
$70$
- C
$105$
- D
$140$
Similar Questions
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