The length of the minute hand of a clock is $5\, cm$. Find the area swept by the minute hand during the time period $6: 05$ $a.m.$ and $6: 40$ $a.m.$ (in $cm^2$)
$45 \frac{5}{6}$
$55 \frac{5}{6}$
$45 \frac{7}{6}$
$55 \frac{7}{6}$
As shown in the diagram, the length of square $A B C D$ is $21\, cm .$ $\widehat{ A P C }$ is an arc of $\odot(B, BA )$ and $\widehat{A Q C}$ is an arc of $\odot( D , DA ) .$ Find the area of the shaded (ruled) portion. (in $cm^2$)
The length of the minute hand of a clock is $7\,cm$. The area of the region swept by it in $20$ minutes is $\ldots \ldots \ldots . cm ^{2}$.
In a circle with radius $42\, cm$, a minor arc subtends an angle of measure $60$ at the centre. Find the area of the minor sector and the minor segment corresponding to this arc. $(\sqrt{3}=1.73)$
In $\odot( O , 12)$, minor $\widehat{ ACB }$ subtends an angle of measure $30$ at the centre. Then. the length of major $\widehat{A D B}$ is $\ldots \ldots \ldots . . cm .$
In a circle with radius $6\, cm ,$ a minor are subtends an angle of measure $60$ at the centre. Find the area of the minor sector and the major sector corresponding to that arc.