The half-life of a radioactive nuclide is 100 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The activity $A$ of a radioactive sample at time $t$ is given by the formula $A = A_{0} \left(\frac{1}{2}\right)^{t/T_{H}}$,where $A_{0}$ is the i

Vedclass · Accepted Answer

$\frac{1}{2 \sqrt{2}}$

Vedclass · Answer

(B) The activity $A$ of a radioactive sample at time $t$ is given by the formula $A = A_{0} \left(\frac{1}{2}\right)^{t/T_{H}}$,where $A_{0}$ is the initial activity and $T_{H}$ is the half-life.Given $T_{H} = 100 \, hours$ and $t = 150 \, hours$.The fraction of activity remaining is $\frac{A}{A_{0}} = \left(\frac{1}{2}\right)^{150/100}$.This simplifies to $\left(\frac{1}{2}\right)^{1.5} = \left(\frac{1}{2}\right)^{3/2} = \frac{1}{2^{3/2}} = \frac{1}{2 \sqrt{2}}$.

The half-life of a radioactive nuclide is $100 \, hours$. The fraction of original activity that will remain after $150 \, hours$ would be:

Similar Questions

The half-life period of a radioactive sample is $T$. If a fraction $x$ disintegrates in time $t$,what fraction will decay in time $\frac{t}{2}$?

$A$ radioactive element initially has $4 \times 10^{16}$ active nuclei. If its half-life is $10 \ days$,find the number of nuclei that have decayed in $30 \ days$.

$A$ radioactive element of mass $1 \,kg$ after $N$ years is left with only $125 \,g$. If the half-life of the element is $12.5 \,y$, then the value of $N$ is:

If the half-life of a radioactive atom is $2.3 \, days$,then its decay constant would be

The relation between half-life $(T)$ and decay constant $(\lambda)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module