The general solution of the equation $\tan^2 x = 1$ is

  • A
    $n \pi + \frac{\pi}{4}$
  • B
    $n \pi - \frac{\pi}{4}$
  • C
    $n \pi \pm \frac{\pi}{4}$
  • D
    $2 n \pi \pm \frac{\pi}{4}$

Explore More

Similar Questions

The set $\{x \in R: \cos 2x + 2 \cos^2 x = 2\}$ is equal to

The solution set of the equation $\tan (\pi \tan x) = \cot (\pi \cot x)$ for $x \in (0, \frac{\pi}{2})$ is

The number of solutions of the equation $4 \cos 2 \theta \cdot \cos 3 \theta = \sec \theta$,when $0 < \theta < \pi$,is

The number of solutions of the equation $\cos^2 2x + \cos^2 \frac{5x}{4} = \cos 2x \cos^2 5x$ in the interval $[0, \frac{\pi}{3}]$ is:

Solve $\tan 2x = -\cot \left(x + \frac{\pi}{3}\right)$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo