Number of solution (s) of the equation { | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\left( {{{\cos }^2}2x - \cos x{{\cos }^2}5x + {{\cos }^4}\frac{{5x}}{4}} \right) + \frac{{{{\cos }^2}5x\left( {1 - {{\cos }^2}5x} \right)}}{4} = 0$

Vedclass · Accepted Answer

$0$

Vedclass · Answer

$\left( {{{\cos }^2}2x - \cos x{{\cos }^2}5x + {{\cos }^4}\frac{{5x}}{4}} \right) + \frac{{{{\cos }^2}5x\left( {1 - {{\cos }^2}5x} \right)}}{4} = 0$

$\cos 2 x=\frac{\cos ^{2} 5 x}{2} \& \sin 10 x=0$

$x=\frac{n \pi}{10}$

$x=0, \frac{\pi}{10}, \frac{2 \pi}{10^{\prime}} \frac{3 \pi}{10}$

No solution

Number of solution $(s)$ of the equation ${\cos ^2}2x + {\cos ^2}\frac{{5x}}{4} = \cos 2x\,{\cos ^2}5x$ in $\left[ {0,\frac{\pi }{3}} \right]$ is

Similar Questions

If $0 \le x \le \pi $ and ${81^{{{\sin }^2}x}} + {81^{{{\cos }^2}x}} = 30$, then $x =$

The only value of $x$ for which ${2^{\sin x}} + {2^{\cos x}} > {2^{1 - (1/\sqrt 2 )}}$ holds, is

If $\sqrt 2 \sec \theta + \tan \theta = 1,$ then the general value $\theta $ is

The solution of $tan\,\, 2\theta\,\, tan\theta = 1$ is

The solution set of the equation $tan(\pi\, tanx) = cot(\pi\, cot\, x)$ is