(C) The force per unit length on a current-carrying conductor in a magnetic field is given by the formula: $\frac{F}{l} = iB \sin \theta$. Here,the cu

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(C) The force per unit length on a current-carrying conductor in a magnetic field is given by the formula: $\frac{F}{l} = iB \sin \theta$. Here,the current $i = 1 \,A$ flows from south to north. The magnetic field $B = 3 \times 10^{-5} \,T$ also points from south to north. Since the current and the magnetic field are in the same direction,the angle $\theta$ between them is $0^\circ$. Therefore,the force per unit length is: $\frac{F}{l} = 1 \times (3 \times 10^{-5}) \times \sin(0^\circ) = 1 \times (3 \times 10^{-5}) \times 0 = 0 \,N/m$.

Class 12 Physics Moving Charges and Magnetism Force on a Current Carrying Conductor

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The force acting per unit length on a very long straight conductor carrying a steady current of $1 \,A$ flowing from south to north is: (The horizontal component of the earth's magnetic field at the place is $3 \times 10^{-5} \,T$ and its direction is from geographical south to geographical north.)

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A
$3 \times 10^{-5} \,N/m$
B
$1 \times 10^{-5} \,N/m$
C
$0$
D
$1.5 \times 10^{-5} \,N/m$

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Moving Charges and Magnetism

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Force on a Current Carrying Conductor

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DifficultJEE MAIN 2024

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The force acting per unit length on a very long straight conductor carrying a steady current of $1 \,A$ flowing from south to north is: (The horizontal component of the earth's magnetic field at the place is $3 \times 10^{-5} \,T$ and its direction is from geographical south to geographical north.)

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Through two parallel wires $A$ and $B$,$10 \, A$ and $2 \, A$ of currents are passed respectively in opposite directions. If the wire $A$ is infinitely long and the length of the wire $B$ is $2 \, m$,the force on the conductor $B$,which is situated at a $10 \, cm$ distance from $A$,will be:

Two long straight parallel conductors are carrying currents $i_1$ and $i_2$ in the same direction. The work done per unit length,when the distance between them is doubled,is:

$A$ current of $3\, A$ is flowing in a linear conductor of length $40\, cm$. The conductor is placed in a magnetic field of strength $500\, G$ and makes an angle of $30^\circ$ with the direction of the field. The magnitude of the force experienced by the conductor is:

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