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(A) The force per unit length between two long parallel wires carrying currents $I_1$ and $I_2$ separated by a distance $d$ is given by $F = \frac{\mu

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(A) The force per unit length between two long parallel wires carrying currents $I_1$ and $I_2$ separated by a distance $d$ is given by $F = \frac{\mu_0 I_1 I_2}{2 \pi d}$.According to the problem,if the currents are in the same direction,$I_1 I_2 > 0$,the wires attract each other,and the force $F$ is defined as 'negative'.If the currents are in opposite directions,$I_1 I_2 Thus,the relationship is $F = -k(I_1 I_2)$,where $k = \frac{\mu_0}{2 \pi d}$ is a positive constant.This represents a straight line passing through the origin with a negative slope. Therefore,the graph showing the dependence of $F$ on $I_1 I_2$ is a straight line in the second and fourth quadrants,which corresponds to graph $A$.

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