(C) The force $F$ experienced by a current-carrying conductor in a magnetic field is given by the formula: $F = B I L \sin \theta$. Given: Current $I

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(C) The force $F$ experienced by a current-carrying conductor in a magnetic field is given by the formula: $F = B I L \sin \theta$. Given: Current $I = 3\, A$,Length $L = 40\, cm = 0.4\, m$,Magnetic field $B = 500\, G = 500 \times 10^{-4}\, T = 0.05\, T$,Angle $\theta = 30^\circ$. Substituting the values: $F = (0.05) \times 3 \times 0.4 \times \sin(30^\circ)$ $F = 0.05 \times 3 \times 0.4 \times 0.5$ $F = 0.03\, N = 3 \times 10^{-2}\, N$.

Class 12 Physics Moving Charges and Magnetism Force on a Current Carrying Conductor

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$A$ current of $3\, A$ is flowing in a linear conductor of length $40\, cm$. The conductor is placed in a magnetic field of strength $500\, G$ and makes an angle of $30^\circ$ with the direction of the field. The magnitude of the force experienced by the conductor is:

A
$3 \times 10^4\, N$
B
$3 \times 10^2\, N$
C
$3 \times 10^{-2}\, N$
D
$3 \times 10^{-4}\, N$

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Moving Charges and Magnetism

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Force on a Current Carrying Conductor

$A$ square loop of length $L$ is placed with its edges parallel to the $XY$-axes. The loop carries a current $I$. If the magnetic field in the region varies as $B = B_0 \left(1 + \frac{xy}{L^2}\right) \hat{k}$,then the magnitude of the net force on the loop will be:

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$A$ wire is bent in the form of an equilateral triangle of side $100 \,cm$ and carries a current of $2 \,A$. It is placed in a magnetic field of induction $2.0 \,T$ directed perpendicular into the plane of paper. The direction and magnitude of magnetic force acting on each side of the triangle will be

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Currents of $10\, A$ and $2\, A$ are passed through two parallel thin wires $A$ and $B$ respectively in opposite directions. Wire $A$ is infinitely long and the length of wire $B$ is $2\, m$. The force acting on the conductor $B$,which is situated at a distance of $10\, cm$ from $A$,will be:

MediumAIEEE 2012

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Two long straight wires $A$ and $B$ carrying equal current $I$ were kept parallel to each other at distance $d$ apart. The magnitude of the magnetic force experienced by length $L$ of wire $A$ is $F$. If the distance between the wires is halved and the currents are doubled,the force $F_2$ on length $L$ of wire $A$ will be:

MediumMHT CET 2025

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$A$ $3.0 \; cm$ wire carrying a current of $10 \; A$ is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be $0.27 \; T$. What is the magnetic force on the wire?

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$A$ current of $3\, A$ is flowing in a linear conductor of length $40\, cm$. The conductor is placed in a magnetic field of strength $500\, G$ and makes an angle of $30^\circ$ with the direction of the field. The magnitude of the force experienced by the conductor is:

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$A$ square loop of length $L$ is placed with its edges parallel to the $XY$-axes. The loop carries a current $I$. If the magnetic field in the region varies as $B = B_0 \left(1 + \frac{xy}{L^2}\right) \hat{k}$,then the magnitude of the net force on the loop will be:

Currents of $10\, A$ and $2\, A$ are passed through two parallel thin wires $A$ and $B$ respectively in opposite directions. Wire $A$ is infinitely long and the length of wire $B$ is $2\, m$. The force acting on the conductor $B$,which is situated at a distance of $10\, cm$ from $A$,will be:

$A$ $3.0 \; cm$ wire carrying a current of $10 \; A$ is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be $0.27 \; T$. What is the magnetic force on the wire?

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