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Question

$7 	imes 10^{-9}=\mathrm{K} 	imes\left(8 	imes 10^{-5}ight)^{\mathrm{x}}\left(8 	imes 10^{-5}ight)^{\mathrm{y}} \ldots \ldots . .(1)$

$2.1

Vedclass · Accepted Answer

$1$

Vedclass · Answer

$7 	imes 10^{-9}=\mathrm{K} 	imes\left(8 	imes 10^{-5}ight)^{\mathrm{x}}\left(8 	imes 10^{-5}ight)^{\mathrm{y}} \ldots \ldots . .(1)$

$2.1 	imes 10^{-8}=\mathrm{K} 	imes\left(24 	imes 10^{-5}ight)^{\mathrm{x}}\left(8 	imes 10^{-5}ight)^{\mathrm{y}} \ldots \ldots (2)$

$\frac{1}{3}=\left(\frac{1}{3}ight)^{\mathrm{x}} \Rightarrow \mathrm{x}=1$

	$[NO]$ $\mathrm{mol} \mathrm{L}^{-1}$	${H}_{2}$ $\mathrm{mol} \mathrm{L}^{-1}$	Rate $\mathrm{mol}L^{-1}$ $s^{-1}$
$(A)$	$8 \times 10^{-5}$	$8 \times 10^{-5}$	$7 \times 10^{-9}$
$(B)$	$24 \times 10^{-5}$	$8 \times 10^{-5}$	$2.1 \times 10^{-8}$
$(C)$	$24 \times 10^{-5}$	$32 \times 10^{-5}$	$8.4 \times 10^{-8}$

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