(A) The rate expression $\frac{dX}{dt} = k[A]^m[B]^n$ indicates that the reaction rate depends only on the concentrations of reactants $A$ and $B$.The

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(A) The rate expression $\frac{dX}{dt} = k[A]^m[B]^n$ indicates that the reaction rate depends only on the concentrations of reactants $A$ and $B$.The order of the reaction with respect to $C$ is $0$,which means the rate of the reaction is independent of the concentration of $C$.Since the rate law is experimentally determined and explicitly excludes $C$,the Reason correctly explains why $C$ does not appear in the rate expression.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

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Assertion : The kinetics of the reaction $mA + nB + pC \to m'X + n'Y + p'Z$ obey the rate expression as $\frac{dX}{dt} = k[A]^m[B]^n$.
Reason : The rate of the reaction does not depend upon the concentration of $C$.

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A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Chemical Kinetics

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Rate law , Rate constant , Order of Reaction and Molecularity

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$A$ reaction $A + B \rightarrow C$ is second order in $A$ and zeroth order in $B$. How is the rate affected when the concentration of $A$ is doubled and $B$ is halved?

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In a reaction,$A + B \rightarrow$ product,the rate is doubled when the concentration of $B$ is doubled,and the rate increases by a factor of $8$ when the concentrations of both the reactants $(A$ and $B)$ are doubled. The rate law for the reaction can be written as:

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$A$ reaction is first order in $A$ and second order in $B$.
$(i)$ Write the differential rate equation.
$(ii)$ How is the rate affected on increasing the concentration of $B$ three times?
$(iii)$ How is the rate affected when the concentrations of both $A$ and $B$ are doubled?

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Under a given set of experimental conditions,with an increase in the concentration of the reactants,the rate of a chemical reaction

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Assertion : The kinetics of the reaction $mA + nB + pC \to m'X + n'Y + p'Z$ obey the rate expression as $\frac{dX}{dt} = k[A]^m[B]^n$.Reason : The rate of the reaction does not depend upon the concentration of $C$.

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The rate of reaction is determined by the slow step of the reaction. This step is called:

$A$ reaction $A + B \rightarrow C$ is second order in $A$ and zeroth order in $B$. How is the rate affected when the concentration of $A$ is doubled and $B$ is halved?

In a reaction,$A + B \rightarrow$ product,the rate is doubled when the concentration of $B$ is doubled,and the rate increases by a factor of $8$ when the concentrations of both the reactants $(A$ and $B)$ are doubled. The rate law for the reaction can be written as:

$A$ reaction is first order in $A$ and second order in $B$.$(i)$ Write the differential rate equation.$(ii)$ How is the rate affected on increasing the concentration of $B$ three times?$(iii)$ How is the rate affected when the concentrations of both $A$ and $B$ are doubled?

Under a given set of experimental conditions,with an increase in the concentration of the reactants,the rate of a chemical reaction

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Assertion : The kinetics of the reaction $mA + nB + pC \to m'X + n'Y + p'Z$ obey the rate expression as $\frac{dX}{dt} = k[A]^m[B]^n$.
Reason : The rate of the reaction does not depend upon the concentration of $C$.

$A$ reaction is first order in $A$ and second order in $B$.
$(i)$ Write the differential rate equation.
$(ii)$ How is the rate affected on increasing the concentration of $B$ three times?
$(iii)$ How is the rate affected when the concentrations of both $A$ and $B$ are doubled?