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(A) The radius of the $n^{th}$ Bohr orbit is given by $r_n = 0.529 	imes \frac{n^2}{Z} \mathring{A}$.For a hydrogen atom,$Z = 1$.Radius of the $3^{rd

Vedclass · Accepted Answer

$2.645 	imes 10^{-8} \ cm$

Vedclass · Answer

(A) The radius of the $n^{th}$ Bohr orbit is given by $r_n = 0.529 	imes \frac{n^2}{Z} \mathring{A}$.For a hydrogen atom,$Z = 1$.Radius of the $3^{rd}$ orbit $(r_3)$ = $0.529 	imes 3^2 = 0.529 	imes 9 = 4.761 \mathring{A}$.Radius of the $2^{nd}$ orbit $(r_2)$ = $0.529 	imes 2^2 = 0.529 	imes 4 = 2.116 \mathring{A}$.The distance between the $3^{rd}$ and $2^{nd}$ orbits is $r_3 - r_2 = 4.761 \mathring{A} - 2.116 \mathring{A} = 2.645 \mathring{A}$.Since $1 \mathring{A} = 10^{-8} \ cm$,the distance is $2.645 	imes 10^{-8} \ cm$.

The distance between the $3^{rd}$ and $2^{nd}$ Bohr's orbits in the hydrogen atom is

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