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(A) The energy of a photon is given by the formula: $E = \frac{hc}{\lambda}$ Given values: $h = 6.62 	imes 10^{-27} \ erg \cdot s$ $c = 3 	imes 10^{

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$3.31 	imes 10^{-12} \ erg$

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(A) The energy of a photon is given by the formula: $E = \frac{hc}{\lambda}$ Given values: $h = 6.62 	imes 10^{-27} \ erg \cdot s$ $c = 3 	imes 10^{10} \ cm/s$ $\lambda = 6000 \ \mathring{A} = 6000 	imes 10^{-8} \ cm = 6 	imes 10^{-5} \ cm$ Substituting the values: $E = \frac{(6.62 	imes 10^{-27} \ erg \cdot s) 	imes (3 	imes 10^{10} \ cm/s)}{6 	imes 10^{-5} \ cm}$ $E = \frac{19.86 	imes 10^{-17}}{6 	imes 10^{-5}} \ erg$ $E = 3.31 	imes 10^{-12} \ erg$

Find the energy of a photon having a wavelength of $6000 \ \mathring{A}$. (Given: $h = 6.62 \times 10^{-27} \ erg \cdot s$)

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