The diameter of the objective of a telescope | vedclass

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Question

(B) Given:Diameter of the objective,$d = 3.6 \ m$Wavelength of light,$\lambda = 540 \ nm = 540 	imes 10^{-9} \ m$The limit of resolution $(d	heta)$

Vedclass · Accepted Answer

$1.83 	imes 10^{-7} \ rad$

Vedclass · Answer

(B) Given:Diameter of the objective,$d = 3.6 \ m$Wavelength of light,$\lambda = 540 \ nm = 540 	imes 10^{-9} \ m$The limit of resolution $(d	heta)$ of a telescope is given by the formula:$d	heta = \frac{1.22 \lambda}{d}$Substituting the values:$d	heta = \frac{1.22 	imes 540 	imes 10^{-9} \ m}{3.6 \ m}$$d	heta = \frac{658.8 	imes 10^{-9}}{3.6} \ rad$$d	heta = 183 	imes 10^{-9} \ rad$$d	heta = 1.83 	imes 10^{-7} \ rad$

The diameter of the objective of a telescope is $3.6 \ m$. The limit of resolution of the telescope for a light of wavelength $540 \ nm$ is

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