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(B) The resolving power $(R.P.)$ of a microscope is given by the formula: $R.P. = \frac{2n \sin \beta}{1.22 \lambda}$.From this expression, it is clea

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Increases

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(B) The resolving power $(R.P.)$ of a microscope is given by the formula: $R.P. = \frac{2n \sin \beta}{1.22 \lambda}$.From this expression, it is clear that the resolving power is inversely proportional to the wavelength of the light used: $R.P. \propto \frac{1}{\lambda}$.Since the wavelength of blue light $(\lambda_{blue})$ is shorter than the wavelength of red light $(\lambda_{red})$, replacing red light with blue light decreases the wavelength $(\lambda)$.Because $\lambda$ decreases, the resolving power $(R.P.)$ increases.Therefore, the correct option is $B$.

If the red light is replaced by blue light illuminating the object in a microscope, the resolving power of the microscope:

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