(D) Given: $9 \, {MSD} = 10 \, {VSD}$.Since $1 \, {MSD} = 1 \, {mm}$,then $10 \, {VSD} = 9 \, {mm}$,so $1 \, {VSD} = 0.9 \, {mm}$.Least Count $({LC})$

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(D) Given: $9 \, {MSD} = 10 \, {VSD}$.Since $1 \, {MSD} = 1 \, {mm}$,then $10 \, {VSD} = 9 \, {mm}$,so $1 \, {VSD} = 0.9 \, {mm}$.Least Count $({LC})$ = $1 \, {MSD} - 1 \, {VSD} = 1 \, {mm} - 0.9 \, {mm} = 0.1 \, {mm} = 0.01 \, {cm}$.Observed Diameter = ${MSR} + ({VSR} \times {LC}) = 10 \, {mm} + (8 \times 0.1 \, {mm}) = 10.8 \, {mm} = 1.08 \, {cm}$.Positive zero error = $0.04 \, {cm}$.Corrected Diameter = $\text{Observed Reading} - \text{Zero Error} = 1.08 \, {cm} - 0.04 \, {cm} = 1.04 \, {cm}$.Radius = $\frac{\text{Diameter}}{2} = \frac{1.04 \, {cm}}{2} = 0.52 \, {cm}$.Expressing in $10^{-2} \, {cm}$: $0.52 \, {cm} = 52 \times 10^{-2} \, {cm}$.Thus,the value is $52$.

Class 11 Physics Units, Dimensions and Measurement Vernier Calipers, Micrometer screw gauge

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The diameter of a spherical bob is measured using a vernier callipers. $9$ divisions of the main scale,in the vernier callipers,are equal to $10$ divisions of vernier scale. One main scale division is $1\, {mm}$. The main scale reading is $10\, {mm}$ and $8^{\text{th}}$ division of vernier scale was found to coincide exactly with one of the main scale division. If the given vernier callipers has positive zero error of $0.04\, {cm}$,then the radius of the bob is $...... \,\times 10^{-2} \,{cm}$.

JEE MAIN 2021 All JEE MAIN

A
$0.52$
B
$520$
C
$5.2$
D
$52$

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Units, Dimensions and Measurement

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Vernier Calipers, Micrometer screw gauge

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$A$ travelling microscope is used to determine the refractive index of a glass slab. If $40$ divisions are there in $1 \; cm$ on the main scale and $50$ Vernier scale divisions are equal to $49$ main scale divisions,then the least count of the travelling microscope is $\dots \times 10^{-6} \; m$.

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If $50$ Vernier divisions are equal to $49$ main scale divisions of a travelling microscope and one smallest reading of main scale is $0.5 \,mm$, the Vernier constant of travelling microscope is:

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In a vernier callipers,$20$ $VSD$ coincide with $16$ $MSD$ (each division of length $1 \text{ mm}$). The least count of the vernier callipers is: (in $\text{ cm}$)

DifficultNEET 2026

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The figure below shows a particular position of the Vernier calipers on a centimetre scale. In this position,the value of $x$ shown in the figure is .......... $cm$ (figure is not to scale).

MediumKVPY 2017

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The main scale division of a vernier caliper is $1 \ mm$. The vernier scale divisions are in an arithmetic progression $(A.P.)$; the $1^{st}$ division is $0.95 \ mm$, the $2^{nd}$ division is $0.90 \ mm$, and so on. When an object is placed between the jaws of the vernier caliper, the zero of the vernier scale lies between $3.1 \ cm$ and $3.2 \ cm$, and the $4^{th}$ division of the vernier scale coincides with a main scale division. The reading of the vernier caliper is .......... $cm$.

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$A$ travelling microscope is used to determine the refractive index of a glass slab. If $40$ divisions are there in $1 \; cm$ on the main scale and $50$ Vernier scale divisions are equal to $49$ main scale divisions,then the least count of the travelling microscope is $\dots \times 10^{-6} \; m$.

If $50$ Vernier divisions are equal to $49$ main scale divisions of a travelling microscope and one smallest reading of main scale is $0.5 \,mm$, the Vernier constant of travelling microscope is:

In a vernier callipers,$20$ $VSD$ coincide with $16$ $MSD$ (each division of length $1 \text{ mm}$). The least count of the vernier callipers is: (in $\text{ cm}$)

The figure below shows a particular position of the Vernier calipers on a centimetre scale. In this position,the value of $x$ shown in the figure is .......... $cm$ (figure is not to scale).

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