The diagram below is formed by three semicirc | vedclass

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(B) The figure consists of one large semicircle with diameter $AB$ and two smaller semicircles with diameters $OA$ and $OB$.Given $OA = 70\, cm$ and $

Vedclass · Accepted Answer

$11550$

Vedclass · Answer

(B) The figure consists of one large semicircle with diameter $AB$ and two smaller semicircles with diameters $OA$ and $OB$.Given $OA = 70\, cm$ and $OB = 70\, cm$,the diameter of the large semicircle is $AB = OA + OB = 70 + 70 = 140\, cm$.The radius of the large semicircle is $R = 140 / 2 = 70\, cm$.The radius of each smaller semicircle is $r = 70 / 2 = 35\, cm$.The area of the large semicircle is $\frac{1}{2} \pi R^2 = \frac{1}{2} 	imes \frac{22}{7} 	imes 70 	imes 70 = 11 	imes 10 	imes 70 = 7700\, cm^2$.The area of the two smaller semicircles is $2 	imes (\frac{1}{2} \pi r^2) = \pi r^2 = \frac{22}{7} 	imes 35 	imes 35 = 22 	imes 5 	imes 35 = 3850\, cm^2$.The total area of the figure is the sum of the area of the large semicircle and the two smaller semicircles: $7700 + 3850 = 11550\, cm^2$.

The diagram below is formed by three semicircles. If $OA = OB = 70\, cm,$ find the area of the figure formed (in $cm^2$).

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