The diagonal passing through the origin of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The vertices of the quadrilateral are formed by the intersection of the lines:$1$. $x=0$ and $y=0$ intersect at $B(0,0)$.$2$. $x=0$ and $6x+y=3$ i

Vedclass · Accepted Answer

$3x - 2y = 0$

Vedclass · Answer

(A) The vertices of the quadrilateral are formed by the intersection of the lines:$1$. $x=0$ and $y=0$ intersect at $B(0,0)$.$2$. $x=0$ and $6x+y=3$ intersect at $A(0,3)$.$3$. $y=0$ and $x+y=1$ intersect at $C(1,0)$.$4$. $x+y=1$ and $6x+y=3$ intersect at $D(\frac{2}{5}, \frac{3}{5})$.The diagonal passing through the origin $B(0,0)$ must also pass through the vertex $D(\frac{2}{5}, \frac{3}{5})$.The equation of a line passing through $(0,0)$ and $(x_1, y_1)$ is $y = \frac{y_1}{x_1}x$.Substituting $x_1 = \frac{2}{5}$ and $y_1 = \frac{3}{5}$:$y = \frac{3/5}{2/5}x$$y = \frac{3}{2}x$$2y = 3x$$3x - 2y = 0$.

The diagonal passing through the origin of a quadrilateral formed by $x = 0, y = 0, x + y = 1$ and $6x + y = 3$ is

Similar Questions

If two opposite vertices of a square are $(5, -4)$ and $(-3, 2)$,find its area.

Let $PQR$ be a triangle in which $PQ=3$. From the vertex $R$,draw the altitude $RS$ to meet $PQ$ at $S$. Assume that $RS=\sqrt{3}$ and $PS=QR$. Then,$PR$ equals

The lines $x+y+4=0$,$x-2y-4=0$,and $3x+4y-2=0$:

Two sides of a rhombus are along the lines $x-y+1=0$ and $7x-y-5=0$. If its diagonals intersect at $(-1,-2)$,then one of the vertices of this rhombus is

$\Delta ABC$ has integral side lengths. The internal angle bisector of angle $B$ meets side $AC$ at $D$. If $AD = 3$ and $DC = 8$,then the perimeter of $\Delta ABC$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module