The area (in square units) of the triangle fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given lines are $x=0$ (the $y$-axis),$y=0$ (the $x$-axis),and $3x+4y=12$.To find the intercepts of the line $3x+4y=12$,we rewrite it in the in

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The given lines are $x=0$ (the $y$-axis),$y=0$ (the $x$-axis),and $3x+4y=12$.To find the intercepts of the line $3x+4y=12$,we rewrite it in the intercept form $\frac{x}{a} + \frac{y}{b} = 1$:$\frac{3x}{12} + \frac{4y}{12} = \frac{12}{12} \implies \frac{x}{4} + \frac{y}{3} = 1$.This line intersects the $x$-axis at $A(4, 0)$ and the $y$-axis at $B(0, 3)$.The triangle formed by the lines $x=0, y=0$,and $3x+4y=12$ is a right-angled triangle with vertices at $O(0, 0)$,$A(4, 0)$,and $B(0, 3)$.The base of the triangle is $OA = 4$ units and the height is $OB = 3$ units.Area of $	riangle OAB = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 4 	imes 3 = 6$ square units.

The area (in square units) of the triangle formed by the lines $x=0, y=0$ and $3x+4y=12$ is:

Similar Questions

Given two points $A(3, 4)$ and $B(5, -2)$. If $PA = PB$ and the area of $\Delta PAB = 10$ square units,find the coordinates of point $P$.

The area of the triangle enclosed by the straight lines $x = 0$,$y = 0$ and $x + 2y + 3 = 0$ in sq. units is:

Points inside the triangle with vertices at $(1,3), (5,0)$ and $(-1,2)$ must necessarily satisfy which of the following conditions?

The four points whose coordinates are $(2, 1), (1, 4), (4, 5), (5, 2)$ form:

The incentre of the triangle formed by the lines $x+y=1$,$x=1$,and $y=1$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module