If a pair of perpendicular lines through the origin together with the straight line $2x + 3y = 6$ form an isosceles triangle,then the area of that triangle (in sq units) is

  • A
    $\frac{6}{\sqrt{13}}$
  • B
    $\frac{6}{13}$
  • C
    $\frac{36}{13}$
  • D
    $\frac{27}{13}$

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