The cost of erecting a wall all around a circ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The circumference of the circular ground is given by: $	ext{Circumference} = \frac{	ext{Total Cost}}{	ext{Rate per meter}} = \frac{26,400}

Vedclass · Accepted Answer

$770$

Vedclass · Answer

(C) $1$. The circumference of the circular ground is given by: $	ext{Circumference} = \frac{	ext{Total Cost}}{	ext{Rate per meter}} = \frac{26,400}{60} = 440 \ m$.$2$. Let the radius of the ground be $r$. The formula for circumference is $2\pi r = 440$.$3$. Using $\pi = \frac{22}{7}$, we get $2 	imes \frac{22}{7} 	imes r = 440$, which simplifies to $r = \frac{440 	imes 7}{44} = 70 \ m$.$4$. The area of the circular ground is $A = \pi r^2 = \frac{22}{7} 	imes 70 	imes 70 = 22 	imes 10 	imes 70 = 15,400 \ m^2$.$5$. The cost of levelling the ground at $₹ 50/m^2$ is $15,400 	imes 50 = ₹ 7,70,000$.

The cost of erecting a wall all around a circular ground at the rate of $₹ 60/m$ is $₹ 26,400$. Find the cost of levelling the ground at the rate of $₹ 50/m^2$. (in $₹$) (in $1,000$)

Similar Questions

In a circle with radius $56 \, cm$,find the area of the minor sector,the major sector,and the minor segment corresponding to two radii perpendicular to each other.

The radius of a circle is $12 \, cm$. Find its circumference and area $(\pi = 3.14)$.

The maximum area of a triangle inscribed in a semicircle having radius $10 \, cm$ is $\ldots \ldots \ldots \, cm^2$.

In a circle with centre $O$,$\overline{OA}$ and $\overline{OB}$ are radii perpendicular to each other. The perimeter of the sector formed by these radii is $75 \, cm$. Find the area of the corresponding minor segment. (in $cm^2$)

Find the area of the shaded region in the given figure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module