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(D) The length of the arc of the circle is given as $20 \,cm$.The central angle subtended by the arc is $	heta = 60^{\circ}$.The formula for the leng

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$\frac{60}{\pi}$

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(D) The length of the arc of the circle is given as $20 \,cm$.The central angle subtended by the arc is $	heta = 60^{\circ}$.The formula for the length of an arc is $L = \frac{	heta}{360^{\circ}} 	imes 2 \pi r$.Substituting the given values into the formula:$20 = \frac{60^{\circ}}{360^{\circ}} 	imes 2 \pi r$Simplify the fraction:$20 = \frac{1}{6} 	imes 2 \pi r$$20 = \frac{\pi r}{3}$Solving for $r$:$r = \frac{20 	imes 3}{\pi} = \frac{60}{\pi} \,cm$.Thus,the radius of the circle is $\frac{60}{\pi} \,cm$.

$A$ piece of wire $20 \,cm$ long is bent into the form of an arc of a circle subtending an angle of $60^{\circ}$ at its centre. Find the radius of the circle. (in $cm$)

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