The circumference of a circle whose area is 2 | vedclass

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(C) Let the radius of the circle be $r\, m$.The area of the circle is given by the formula $A = \pi r^{2}$.Given $A = 24.64\, m^{2}$,we have $\frac{22

Vedclass · Accepted Answer

$17.6$

Vedclass · Answer

(C) Let the radius of the circle be $r\, m$.The area of the circle is given by the formula $A = \pi r^{2}$.Given $A = 24.64\, m^{2}$,we have $\frac{22}{7} 	imes r^{2} = 24.64$.Solving for $r^{2}$: $r^{2} = \frac{24.64 	imes 7}{22} = 1.12 	imes 7 = 7.84$.Taking the square root: $r = \sqrt{7.84} = 2.8\, m$.The circumference of the circle is given by $C = 2 \pi r$.Substituting the value of $r$: $C = 2 	imes \frac{22}{7} 	imes 2.8 = 2 	imes 22 	imes 0.4 = 17.6\, m$.

The circumference of a circle whose area is $24.64\, m^{2}$ is ....... $m$.

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