The circumference of a circular field is 440 | vedclass

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(B) The circumference of the circular field is $2 \pi r = 440 \, m$.$2 	imes \frac{22}{7} 	imes r = 440 \, m \Rightarrow r = 70 \, m$.The width of t

Vedclass · Accepted Answer

$3300$

Vedclass · Answer

(B) The circumference of the circular field is $2 \pi r = 440 \, m$.$2 	imes \frac{22}{7} 	imes r = 440 \, m \Rightarrow r = 70 \, m$.The width of the path is $10 \, m$.The radius of the outer circle is $R = r + 10 = 70 + 10 = 80 \, m$.The area of the path is $\pi(R^2 - r^2) = \frac{22}{7} 	imes (80^2 - 70^2) = \frac{22}{7} 	imes (6400 - 4900) = \frac{22}{7} 	imes 1500 \, m^2$.The rate of gravelling is $70 \, 	ext{paise} = 0.70 \, Rs. / m^2$.The total cost $= 	ext{Area} 	imes 	ext{Rate} = \frac{22}{7} 	imes 1500 	imes 0.70 = 22 	imes 1500 	imes 0.1 = 3300 \, Rs.$

The circumference of a circular field is $440 \, m$. $A$ circular path of $10 \, m$ width runs around the outside of the field. Find the cost of gravelling the path at the rate of $70 \, \text{paise}$ per square metre? (in $Rs.$)

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