In the given figure,$OP = PQ = 14 \, cm$ and semicircles are drawn on $OP$,$PQ$,and $OQ$ as diameters. Then,the perimeter of the shaded area is . . . . . . $cm$.

  • A
    $88$
  • B
    $176$
  • C
    $264$
  • D
    $352$

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