The Boolean expression for the following comb | vedclass

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(C) The given circuit consists of two $NOT$ gates,two $AND$ gates,and one $OR$ gate.$1$. The input $A$ passes through a $NOT$ gate to become $\overlin

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$(\overline{A} \cdot B)+(A \cdot \overline{B})$

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(C) The given circuit consists of two $NOT$ gates,two $AND$ gates,and one $OR$ gate.$1$. The input $A$ passes through a $NOT$ gate to become $\overline{A}$,and input $B$ goes directly to the first $AND$ gate. The output of this $AND$ gate is $\overline{A} \cdot B$.$2$. The input $B$ passes through a $NOT$ gate to become $\overline{B}$,and input $A$ goes directly to the second $AND$ gate. The output of this $AND$ gate is $A \cdot \overline{B}$.$3$. These two outputs are then fed into an $OR$ gate. The final output $Y$ is the sum of these two expressions: $Y = (\overline{A} \cdot B) + (A \cdot \overline{B})$.This is the Boolean expression for an $XOR$ gate.

The Boolean expression for the following combination is

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