The logic gate equivalent to the combination | vedclass

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Question

(A) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate. Let the inputs be $A$ and $B$. The outputs of the two $NOT$ gates are $\ba

Vedclass · Accepted Answer

$AND$

Vedclass · Answer

(A) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate. Let the inputs be $A$ and $B$. The outputs of the two $NOT$ gates are $\bar{A}$ and $\bar{B}$. These are the inputs to the $NOR$ gate. The output $y$ of the $NOR$ gate is given by $y = \overline{\bar{A} + \bar{B}}$. Using De Morgan's theorem,$\overline{\bar{A} + \bar{B}} = \overline{\bar{A}} \cdot \overline{\bar{B}} = A \cdot B$. The expression $y = A \cdot B$ represents an $AND$ gate. Therefore,the combination is equivalent to an $AND$ gate.

$A$	$B$	$Y$
$0$	$0$	$0$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$1$

The logic gate equivalent to the combination of logic gates shown in the figure is

Similar Questions

The truth table given below represents which logic gate?
$A$ $B$ $Y$
$0$ $0$ $0$
$0$ $1$ $1$
$1$ $0$ $1$
$1$ $1$ $1$

The Boolean expression for the following combination is

If $A$ and $B$ are two inputs in an $AND$ gate,then the $AND$ gate has an output of $1$ when the values of $A$ and $B$ are:

In a negative logic system,the following waveform corresponds to which binary sequence?

The output $W$ for the given logic circuit is:

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