If the output of A + bar B is Y = 0,then the | vedclass

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(C) The given Boolean expression is $Y = A + \bar B$.To find the inputs for which $Y = 0$,we construct the truth table:      $A$    $B$    $\bar B$

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$A = 0, B = 1$

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(C) The given Boolean expression is $Y = A + \bar B$.To find the inputs for which $Y = 0$,we construct the truth table:      $A$    $B$    $\bar B$    $Y = A + \bar B$        $1$    $1$    $0$    $1 + 0 = 1$        $1$    $0$    $1$    $1 + 1 = 1$        $0$    $1$    $0$    $0 + 0 = 0$        $0$    $0$    $1$    $0 + 1 = 1$  From the truth table,it is clear that the output $Y = 0$ only when $A = 0$ and $B = 1$.

If the output of $A + \bar B$ is $Y = 0$,then the inputs are .......

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You are given two circuits as shown in the figure. Show that circuit $(a)$ acts as an $OR$ gate while circuit $(b)$ acts as an $AND$ gate.

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